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18n^2-27n+10=0
a = 18; b = -27; c = +10;
Δ = b2-4ac
Δ = -272-4·18·10
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3}{2*18}=\frac{24}{36} =2/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3}{2*18}=\frac{30}{36} =5/6 $
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